Anonymous

P(x)= 6x^3 + 25x^2 - 8x - 48 ? P(-4) = 6(-4)^3 + 25(-4)^2 - 8(-4) - 48 = 0 x + 4 is a factor of P(x) Divide P(x) by x + 4 to get P(x) = (x + 4)(6x^2 + x - 12) Now factorise 6x^2 + x - 12 P(x) = (x + 4)(3x - 4)(2x + 3)

Anonymous

=> 1. find possible rational roots 2. using synthetic division P(x)= 6x^3+25x^2-8x-48 = (x+4)(6x^2+x-12) = (x-4)(2x+3)(3x-4)

Anonymous

(6x³+25x²-8x-48) ÷ (x+4) = 6x²+x-12 6x²+x-12 = (3x-4)(2x+3) 6x³+25x²-8x-48 = (x+4)(3x-4)(2x+3)