What is the vertex of the parabola? y+4=1/2(x−7)2?

Science & Mathematics by Anonymous 2018-05-11 11:08:41

Social Science

7 answers

Will give best answer. Thank you

Anonymous

y + 4 = 1/2(x - 7)^2 y = 1/2(x - 7)^2 - 4 vertex is (7, -4)
Anonymous

(7, -4). In vertex form you have y = (1/2)(x - 7)^2 - 4. The general vertex form is y = a(x - h)^2 + k, with (h, k) as the vertex. h = 7, k = -4.
Anonymous

y+4 = ½(x-7)² y = ½(x-7)² - 4 vertex (7,-4)
Anonymous

At the vertex, x is 7 and so y is -4. Answer (7,-4).
Anonymous

parabola focus | (7, -7/2) = (7, -3.5) vertex | (7, -4) semi-axis length | 1/2 = 0.5 focal parameter | 1 eccentricity | 1 directrix | y = -9/2
Anonymous

Ans:
Anonymous

vertex form y = a(x - h)^2 + k; vertex is (h,k) y = 0.5(x - 7)^2 - 4 vertex = (7, -4)