The area of a rectangular patio is 800 ft 2 . The patio’s length is twice its width. Find the dimensions of the patio.?

Science & Mathematics by Anonymous 2018-05-11 11:09:31

Social Science

6 answers

Please help me on this im so confused

Anonymous

LW = 800 L = 2W (2W)W = 800 W² = 400 W = 20 ft L = 2W = 40 ft
Anonymous

2w= L L * w= 800 2w * w= 800 2w^2= 800 W^2 = 400 W= 20 20*2= 40 20 by 40 feet patio
Anonymous

Rectangular so we know L x W = Area given L = 2W So we now have 2W x W = 800 w² = 400 Take square root of both sides: w = 20ft L = 40ft
Anonymous

2w^2 = 800 width = 20 ft length = 40 ft
Anonymous

2w^2 = 800 ft^2 w^2 = 400 ft^2 w = 20 ft l = 40 ft
Anonymous

20ft x 40ft