Anonymous

An object has a constant acceleration of 40 ft/sec^2, an initial velocity of -20 ft/sec, and an initial position of 10 ft. Find the position function, s(t), describing the motion of the object. a = 40, v_0 = -20, d_0 = 10 s(t) = 10 - 20t + (1/2)(40)t^2

Anonymous

v(t) = 40t + C where C = -20 v(t) = 40t - 20 s(t) = 20t^2-20t+D where D = 10 s(t) = 20t^2-20t+10